How many x intercepts does P(x)= x²-2x-48 have
Math
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Question
How many x intercepts does P(x)= x²-2x-48 have
1 Answer
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1. User Answers AGboii
ANSWER⤵️
- 2
substitute 0 to Y to get the x intercepts
P(x) = y
y=x²-2x-48
0=x²-2x-48
0=(x-8)(x+6)
x-8=0 , x+6=0
x=8 , x=-6
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