the velocity of a car at 10:50 a.m. is 60 km per hour and at 10:52 a.m. it is 80km/h .assuming constant acceleration in the given period ,find its value
Question
2 Answer

1. User Answers Anonym
Answer :
Given
▪️Velocity at 10:50 am = 60 km/h
= 60 × 5/18
= 150/9 m/s
▪️Velocity at 10:52 am = 80 km/h
= 80 × 5/18
= 200/9 m/s
▪️Acceleration is constant
Now from above
▪️Time = 2 min = 120 sec
Now as we have
▪️v = u + at
[tex]\longrightarrow \dfrac{200}{9}= \dfrac{150}{9} + 120(a) [/tex]
[tex]\longrightarrow \dfrac{200}{9} \dfrac{150}{9} = 120(a) [/tex]
[tex]\longrightarrow \dfrac{200  150}{9}= 120(a) [/tex]
[tex]\longrightarrow \dfrac{50}{9}= 120(a) [/tex]
[tex]\longrightarrow a = \dfrac{\dfrac{50}{9}}{120} [/tex]
[tex]\longrightarrow a = \dfrac{50}{9\times120}[/tex]
[tex]\longrightarrow a = \dfrac{5}{9\times12}[/tex]
[tex]\longrightarrow a = \dfrac{5}{108}[/tex]

2. User Answers manishpalha
v = 80km/h
u = 60 km/h
v u = 20 km/h
= 20*5/18 m/s
= 100÷18 m/s
t = 2 minutes = 2*60 s = 120 sec
according to first law of motion
v = u + at
a = (vu)/ t
a=100÷18÷120 m/s^2
= 0.0462 m/s^×