ball is projected vertically upwards is at a distance of S ft from the projection point after t seconds , where s=64t-16t^2. will the ball ever be 80 ft above the ground

2 Answer

  • no, ball will not go higher than 64ft

  • Answer:

    Ball will never be 80ft above the ground.

    Step-by-step explanation:

    Consider the provided information.

    The provided function is [tex]s=64t-16t^2[/tex]

    Here the coefficient of the t² is negative so the maximum will exist at the vertex.

    We can find the value of vertex by using the formula: [tex]x =\frac{-b}{2a}[/tex]

    Substitute the value of b = 64 and a = -16

    [tex]t =\frac{-64}{2(-16)}[/tex]  

    [tex]t =2[/tex]

    Now substitute the value of t = 2 in the provided function.




    Hence, the maximum height can be 64ft.

    Ball will never be 80ft above the ground.

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