ball is projected vertically upwards is at a distance of S ft from the projection point after t seconds , where s=64t16t^2. will the ball ever be 80 ft above t
Math
sweetha16ei
Question
ball is projected vertically upwards is at a distance of S ft from the projection point after t seconds , where s=64t16t^2. will the ball ever be 80 ft above the ground
2 Answer

1. User Answers Anonym
no, ball will not go higher than 64ft

2. User Answers FelisFelis
Answer:
Ball will never be 80ft above the ground.
Stepbystep explanation:
Consider the provided information.
The provided function is [tex]s=64t16t^2[/tex]
Here the coefficient of the t² is negative so the maximum will exist at the vertex.
We can find the value of vertex by using the formula: [tex]x =\frac{b}{2a}[/tex]
Substitute the value of b = 64 and a = 16
[tex]t =\frac{64}{2(16)}[/tex]
[tex]t =2[/tex]
Now substitute the value of t = 2 in the provided function.
[tex]s=64(2)16(2)^2[/tex]
[tex]s=12864[/tex]
[tex]s=64[/tex]
Hence, the maximum height can be 64ft.
Ball will never be 80ft above the ground.