solve: x square + 3x + 2x+6=0​

[tex]x^{2} + 3x + 2x + 6 = 0[/tex]

[tex]x(x + 3) + 2(x + 3) = 0[/tex]

[tex](x + 3)(x + 2) = 0[/tex]

[tex]either[/tex]

[tex]x + 3 = 0[/tex]

[tex]x = 3[/tex]

[tex]or[/tex]

[tex]x + 2 = 0[/tex]

[tex]x = - 2[/tex]

Solution

x^2+3x+2x+6=0

x^2+5x+6=0

x^2+3x+2x+6=0

x(x+3)+2(x+3) =0

(x+3)(x+2)=0

x=-3 and x= -2

hope this helps!!♥✌