the sum of the squares of two numbers is 233 and one of the numbers is 3 less than twice the other number. find the numbers
Math
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Question
the sum of the squares of two numbers is 233 and one of the numbers is 3 less than twice the other number. find the numbers
1 Answer

1. User Answers hardhik1
let 1 no be x
another number be y
therefore sum of the squares of 2 nos(x&y) is given by. x2+y2=233. 1
one of the no(x) is 3 less than twice the other no(y)
x=2y3. 2
substitute 2 in 1
we get,
(2y3)2+y2=233
4y2+912y=233
4y212y=224
4y212y224=0
take 4 common
the equation becomes
y23y56=0
by the formula
see top
next x=2 ×3+root (233)/23
x=root (233) will be the answer
For y u see image