Mathematics

Question

Part A: Factor 5x2b2 + 14xb2 − 3b2. Show your work.
Part B: Factor x2 − 18x + 81. Show your work.
Part C: Factor x2 − 121. Show your work.

1 Answer

  • Part A:
     
    We have the following expression:
     5x2b2 + 14xb2 - 3b2
     Rewriting we have:
     b2 (5x2 + 14x - 3)
     b2 (5x-1) (x + 3)

     Part B:
     We have the following expression:
     x2 - 18x + 81
     Rewriting we have:
     (x-9) (x-9)
     (x-9) ^ 2

     
    Part C:
     
    We have the following expression:
     x2 - 121
     Rewriting we have:
     (x-11) (x + 11)